Question

calcium carbonate is the major component of limestone and marble. sulphuric acid is one of the major component of acid rain. write a balanced chemical equation that how sulphuric acid react with calcium carbonent

Answer 1

It seems like you are trying to write a balanced chemical equation for the reaction between calcium carbonate and sulfuric acid. According to the web search results, calcium carbonate is the major component of limestone and marble and sulfuric acid is one of the major components of acid rain. When these two substances react, they produce calcium sulfate, water, and carbon dioxide. To write a balanced chemical equation, you need to follow some steps and rules. Here is one possible way to do it:

Write the unbalanced equation to show the reactants and products. Use the chemical formulas of each substance and place an arrow between them to indicate the direction of the reaction.

CaCO3​+H2​SO4​→CaSO4​+H2​O+CO2​

Write down how many atoms of each element there are on each side of the reaction arrow. Look at the subscripts next to each atom to find the number of atoms in the equation.

Left side: 1 calcium (Ca), 1 carbon ©, 3 oxygen (O), 2 hydrogen (H), and 1 sulfur (S).

Right side: 1 calcium (Ca), 1 carbon ©, 6 oxygen (O), 2 hydrogen (H), and 1 sulfur (S).

Add coefficients (the numbers in front of the formulas) so the number of atoms of each element is the same on both sides of the equation. Start with single elements or elements that appear in only one compound on each side. Do not change the subscripts or the chemical formulas.

To balance the oxygen atoms, we need to add a coefficient of 2 in front of CaCO3 on the left side and a coefficient of 3 in front of CO2 on the right side. This gives us:

2CaCO3​+H2​SO4​→CaSO4​+H2​O+3CO2​

Now we have:

Left side: 2 calcium (Ca), 2 carbon ©, 6 oxygen (O), 2 hydrogen (H), and 1 sulfur (S).

Right side: 1 calcium (Ca), 3 carbon ©, 6 oxygen (O), 2 hydrogen (H), and 1 sulfur (S).

To balance the calcium atoms, we need to add a coefficient of 2 in front of CaSO4 on the right side. This gives us:

2CaCO3​+H2​SO4​→2CaSO4​+H2​O+3CO2​

Now we have:

Left side: 2 calcium (Ca), 2 carbon ©, 6 oxygen (O), 2 hydrogen (H), and 1 sulfur (S).

Right side: 2 calcium (Ca), 3 carbon ©, 10 oxygen (O), 2 hydrogen (H), and 2 sulfur (S).

To balance the sulfur atoms, we need to add a coefficient of 2 in front of H2SO4 on the left side. This gives us:

2CaCO3​+2H2​SO4​→2CaSO4​+H2​O+3CO2​

Now we have:

Left side: 2 calcium (Ca), 2 carbon ©, 8 oxygen (O), 4 hydrogen (H), and 2 sulfur (S).

Right side: same as before.

To balance the hydrogen atoms, we need to add a coefficient of 4 in front of H2O on the right side. This gives us:

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∗∗Finalanswer∗∗:2CaCO3​+2H2​SO4​→2CaSO4​+4H2​O+3CO2​

Check your work by counting the atoms of each element on both sides of the equation. They should be equal. If not, go back and adjust the coefficients until they are balanced.

Left side: 2 calcium (Ca), 2 carbon ©, 8 oxygen (O), 4 hydrogen (H), and 2 sulfur (S).

Right side: 2 calcium (Ca), 3 carbon ©, 8 oxygen (O), 4 hydrogen (H), and 2 sulfur (S).

The equation is balanced. I hope this helps you with your homework.