Question

If a radio and a bulb each of resistance 3 ohm are connected in series to a 12 volts battery, the potential difference across each will be;

a) 3V

b) 6V

c) 12V

d) 9V

Can u please solve and then explain answer

Answer 1

`\rm{Option \:B) \: 6V}`

Step-by-step explanation:

Given resistance of the radio is 3Ω and the resistance of the bulb is 3Ω. The total resistance in the circuit is

`R_1 + R_2 = 6 Ω</p><p>`

Now apply Ohm's Law,

`V \:=\: IR`

The voltage of the battery is V = 12V. And we have the total resistance of the circuit. Substituting the values to find current:

`I = 12 V / 6 Ω = 2A`

The potential difference across the radio or the bulb (using V = IR) is:

`V = 3 * 2 = 6V`

~The answer is option(b) 6 volts.