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HELP ME!! I'm trying to pass a challenge test..

solve this equation with the quadratic formula..

HELP ME!! I'm trying to pass a challenge test.. solve this equation with the quadratic-example-1
User Dickeylth
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francoiseaustralie20

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Answer:

3v²+6v+6=0

3v²+6v+6 is an equation of the form:

ax²+bx+c=0

where a,b,c are real coefficients

a=3; b=6; c=6

We set Δ=b²−4ac

. Δ is called the trinomial discriminant ax²+bx+c. The number of solutions of the equation depends on the sign of the discriminant.

Δ<0: no solution

Δ=0:1solution:-b/2a

Δ>0 2solutions

we calculate Δ: 6²-4(3*6)=36-72=-36

Δ<0; no real solution

The discriminant Δ is strictly negative, the equation 3x²+6x+6=0

admits no real solution but admits two COMPLEX solutions:

solution 1: (-b-iV-Δ)/2a =(-6-i6)/6 = -1-i

solution 2: (-b+iV-Δ)/2a= (-6+i6)/6 =- 1+i

Explanation:

User Maxbeaudoin
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