Question

A system does 506 kJ of work and loses 271 kJ of heat to the surroundings. What is the change in internal energy, Δ , of the system? Note that internal energy is symbolized as Δ in some sources.

Answer 1

235 kJ

Step-by-step explanation:

The work W done on the system is equal to the change ΔE in the internal energy plus the heat H lost to the surroundings.

So ΔE = W - H

= 506 kJ - 271 kJ

= 235 kJ