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A system does 506 kJ of work and loses 271 kJ of heat to the surroundings. What is the change in internal energy, Δ , of the system? Note that internal energy is symbolized as Δ in some sources.

User Bajan
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1 Answer

6 votes

Answer:

235 kJ

Step-by-step explanation:

The work W done on the system is equal to the change ΔE in the internal energy plus the heat H lost to the surroundings.

So ΔE = W - H

= 506 kJ - 271 kJ

= 235 kJ

User Djordje Ivanovic
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