The ICE table for the reaction is shown in the answer below for each specie.
Number of moles of
= 0.0432 mol/2 L
= 0.0216 M
Number of moles of oxygen = 0.0296 mol/2 L
= 0.0148 M
Equilibrium concentration of
= 0.01752 M
The ICE table will look like this;
2
(g) +
(g) = 2
(g)
I 0.0216 0.0148 -
C -2x -x +2x
E 0.0216 - 2x 0.0148 - x 0.01752