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Find the cross product (-3, 1, 2) × (5, 1, 6).
Answer:

User J K
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1 Answer

1 vote

Answer:

Hi,

Explanation:


\begin{bmatrix}\vec{i}&\vec{j}&\vec{k}\\-3&1&2\\5&1&6\\\end{bmatrix} =\vec{i}*(1*6-1*2)+\vec{j}*(-1)*(-3*6-2*5)+\vec{k}*(-3*1-5*1)\\\\=4*\vec{i}+28*\vec{j}-8\vec{k}\\\\

User Richard Reddy
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