Question

PLEASE HELP ME TO SOLVE THIS QUESTION TOMORROW IS MY MATHS EXAM.

Answer 1

2.1

5.

Explanation:

2.

m+n=m-n

m+n-m+n=0

2n=0

n=0

`m^n=m^0=1`

5.

`(5^(2077) -5^(2076) )/(20 * 5^(2075) ) \\=(5^(2075).5^2-5^(2075).5^1)/(20 * 5^(2075)) \\=(5^(2075)(5^2-5))/(20 * 5^(2075)) \\=(25-5)/(20) \\=(20)/(20) \\=1`

6.

(x^{a-b))^{a^2+ab+b^2} ×(x^{b-c}^{b^2+bc+c^2} ×(x^{c-a})^{c^2+ca+a^2}

=x^{a^3-b^3)×x^{b^3-c^3} ×x^{c^3-a^3}

=x^{a^3-b^3+b^3-c^3+c^3-a^3]

=x^0

=1