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Solve inquelities 3x-2y<10+x<2+5x and put on number line.

User Wmorrell
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1 Answer

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To solve the inequalities and represent them on a number line, we'll need to work with each inequality separately.

1. 3x - 2y < 10
2. x < 2 + 5x

Let's solve each inequality step by step:

**Inequality 1:**
3x - 2y < 10

First, isolate "y":
-2y < 10 - 3x

Divide both sides by -2 (remember to reverse the inequality when dividing by a negative number):
y > -5 + (3/2)x

**Inequality 2:**
x < 2 + 5x

Subtract "x" from both sides:
0 < 2 + 4x

Subtract "2" from both sides:
-2 < 4x

Divide both sides by 4:
-0.5 < x

Now let's represent these inequalities on a number line:

```
-5 -0.5 2
|-----------|------------|-------->
```

The open circle at -0.5 indicates that x is strictly less than -0.5. The shaded region to the right of the open circle represents values of y greater than -5 + (3/2)x, satisfying the first inequality.
User Dthulke
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