Question

In right triangle ABC, AC=2, BC=2.5, the area of ABC is:

Answer 1

1.875 cm^3

I think that's the answer.

Explanation:

In a right angled triangle,

hypotenuse (AC)= h= 2 cm

base(BC) =b= 2.5 cm

Now,

By Pythagoras theorem,

h^2 = p^2 + b^2

or, (2)^2 = p^2 + (2.5)^2

or, 4 = p^2 + 6.25

or, - p^2 = 6.25- 4

or, p = ±√2.25

or, p= ±1.5

Then,

Area of ABC= 1/2 ×b×p

= 1/2 ×2.5× 1.5

= 1.875 cm^3

Answer 2

1.875 cm^3

I think that's the answer.

Explanation:

In a right angled triangle,

hypotenuse (AC)= h= 2 cm

base(BC) =b= 2.5 cm

Now,

By Pythagoras theorem,

h^2 = p^2 + b^2

or, (2)^2 = p^2 + (2.5)^2

or, 4 = p^2 + 6.25

or, - p^2 = 6.25- 4

or, p = ±√2.25

or, p= ±1.5

Then,

Area of ABC= 1/2 ×b×p

= 1/2 ×2.5× 1.5

= 1.875 cm^3