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Determine the number of atoms of O in 74.8 moles of
Fe₂(SO₃)₃.

User WQYeo
by
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2 Answers

6 votes

Final answer:

To find the number of oxygen atoms in 74.8 moles of Fe₂(SO₃)₃, calculate the total by multiplying the moles by Avogadro's number and then by the number of oxygen atoms per formula unit, resulting in 4.047 x 10² atoms.

Step-by-step explanation:

To determine the number of atoms of O in 74.8 moles of Fe₂(SO₃)₃, we must first identify the number of oxygen atoms in one molecule of the compound. In Fe₂(SO₃)₃, each sulfate ion (SO₃)²⁻ has three oxygen atoms, and there are three sulfate ions, so we have a total of 9 oxygen atoms in one formula unit of Fe₂(SO₃)₃.

We can multiply the number of moles of Fe₂(SO₃)₃ by Avogadro's number (6.022 × 10²³ atoms/mol) and then by the number of oxygen atoms per molecule to find the total number of oxygen atoms:

74.8 moles Fe₂(SO₃)₃ × (6.022 × 10²³ atoms/mol) × 9 O atoms/Fe₂(SO₃)₃ = 4.047 × 10² oxygen atoms.

User Mwallisch
by
8.8k points
3 votes

Final answer:

To find the number of oxygen atoms in 74.8 moles of Fe2(SO3)3, each molecule's 9 oxygen atoms are considered. Multiplying Avogadro's number by 74.8 gives the total molecules, which is then multiplied by 9, yielding 4.052 x 10^26 oxygen atoms.

Step-by-step explanation:

To determine the number of oxygen atoms in 74.8 moles of Fe2(SO3)3, we need to understand the chemical formula. Each molecule of Fe2(SO3)3 contains three sulfate (SO3) groups, and each sulfate group contains three oxygen atoms. Therefore, each molecule contains 3 x 3 = 9 oxygen atoms.

Next, we use Avogadro's number (6.022 x 1023) to determine the number of molecules in one mole. Since there are 74.8 moles of Fe2(SO3)3, we multiply 74.8 by Avogadro's number to get the number of molecules of the compound.

Finally, we multiply the number of molecules by the number of oxygen atoms per molecule (9) to find the total number of oxygen atoms:

74.8 moles Fe2(SO3)3 x (6.022 x 1023 molecules/mole) = 4.502 x 1025 molecules

4.502 x 1025 molecules x 9 atoms O/molecule = 4.052 x 1026 atoms O

Therefore, there are 4.052 x 1026 oxygen atoms in 74.8 moles of Fe2(SO3)3.

User Sahil Raj Thapa
by
8.3k points
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