Final answer:
To find the number of oxygen atoms in 74.8 moles of Fe2(SO3)3, each molecule's 9 oxygen atoms are considered. Multiplying Avogadro's number by 74.8 gives the total molecules, which is then multiplied by 9, yielding 4.052 x 10^26 oxygen atoms.
Step-by-step explanation:
To determine the number of oxygen atoms in 74.8 moles of Fe2(SO3)3, we need to understand the chemical formula. Each molecule of Fe2(SO3)3 contains three sulfate (SO3) groups, and each sulfate group contains three oxygen atoms. Therefore, each molecule contains 3 x 3 = 9 oxygen atoms.
Next, we use Avogadro's number (6.022 x 1023) to determine the number of molecules in one mole. Since there are 74.8 moles of Fe2(SO3)3, we multiply 74.8 by Avogadro's number to get the number of molecules of the compound.
Finally, we multiply the number of molecules by the number of oxygen atoms per molecule (9) to find the total number of oxygen atoms:
74.8 moles Fe2(SO3)3 x (6.022 x 1023 molecules/mole) = 4.502 x 1025 molecules
4.502 x 1025 molecules x 9 atoms O/molecule = 4.052 x 1026 atoms O
Therefore, there are 4.052 x 1026 oxygen atoms in 74.8 moles of Fe2(SO3)3.