Answer:
In this case, the chance of blue eyes is zero. All kids will have exactly one B allele and one b allele, giving all of them them the heterozygous Bb genotype, and expressing the dominant brown phenotype.But let’s make the game more interesting. Dad is now Bb. Mom is still bb. This gives two possibilities. Statistically, half of all children of their union would be genotype Bb/phenotype brown eyes, and half would be genotype bb/phenotype blue eyes.But children aren’t born according to statistics. Each individual pregnancy is a die roll, and the dice have no memory. They could have 12 kids and all of them could be blue eyed. Or all of them could be brown eyed. It would be mathematically unlikely in either case, but it could happen. The more children they have, the more likely they are to regress to the 50/50 mean of brown/blue, but it doesn’t have to happen.
Step-by-step explanation:
hope this helps<3