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The length (in centimeters) of a petal on a certain flower is a random variable with probability density function defined by f(x)=1​/sqrt8x​ for x in [ 1,25 ]. a. Find the expected petal length

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The expected petal length is 1 centimeter.

In this case, the PDF is defined as:


$f(x) = (1)/(2√(x))$ for
$x$ in
$[9, 16]$

To find the expected petal length, we need to calculate the integral of
$x \cdot f(x)$ over the interval
$[9, 16]$.

Let's set up the integral and solve it step by step:


$\text{Expected petal length} = E(X) = \int_(9)^(16) x \cdot f(x) \, dx$


$E(X) = \int_(9)^(16) x \cdot (1)/(2√(x)) \, dx$

To simplify the integral, we can rewrite the expression as:


$E(X) = (1)/(2) \int_(9)^(16) x^{-(1)/(2)} \, dx$

Next, we can use the power rule of integration to solve the integral:


$E(X) = (1)/(2) \left[2x^{(1)/(2)}\right]_(9)^(16)$


$E(X) = \left[x^{(1)/(2)}\right]_(9)^(16)$

Now, substitute the upper and lower limits into the expression:


$E(X) = \left[√(16) - √(9)\right]$


$E(X) = \left[4 - 3\right]$


$E(X) = 1$

User Maulik Kansara
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