The expected petal length is 1 centimeter.
In this case, the PDF is defined as:
for
in
![$[9, 16]$](https://img.qammunity.org/2024/formulas/mathematics/high-school/x6zx13e3dfs5s5q8m9srykctinkqo9qhim.png)
To find the expected petal length, we need to calculate the integral of
over the interval
.
Let's set up the integral and solve it step by step:


To simplify the integral, we can rewrite the expression as:

Next, we can use the power rule of integration to solve the integral:
![$E(X) = (1)/(2) \left[2x^{(1)/(2)}\right]_(9)^(16)$](https://img.qammunity.org/2024/formulas/mathematics/high-school/8dj3hx7ajcmlqjrzogvt8ncogx0oc05zuc.png)
![$E(X) = \left[x^{(1)/(2)}\right]_(9)^(16)$](https://img.qammunity.org/2024/formulas/mathematics/high-school/zssljzcfax8ub0z17utfj1pfblecqvlxx1.png)
Now, substitute the upper and lower limits into the expression:
![$E(X) = \left[√(16) - √(9)\right]$](https://img.qammunity.org/2024/formulas/mathematics/high-school/z62rgzqjzsk3x6zcvcibhzjujervfm5g4d.png)
![$E(X) = \left[4 - 3\right]$](https://img.qammunity.org/2024/formulas/mathematics/high-school/4c38dmdnzv280bugr1chdm8lktv3bwfzvd.png)
