Question

Please help!

Find the slope of the line that passes through these two points

(-3,2) (6,5)

m= y2-y1
X2-x1

M=?
Simplify completely

Answer 1

`(\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{ 3 }{6 +3} \implies \cfrac{ 3 }{ 9 } \implies \cfrac{1}{3}`

Answer 2

y=1/3x+3

Explanation:

find the slope first

y²-y¹/x²-x¹

plug in the corresponding values

5-2/6-(-3)

3/9

1/3

use slope intercept form:

y-y¹=m(x-x¹)

plug in slope for m and pick one of the coordinates for the equation

I will use (-3,2)

y-(2)=1/3(x-(-3))

simplify

y-2=1/3(x+3)

distribute 1/3

y-2=1/3x+1

add 2 to both sides

y=1/3x +3