Question

8. Find the definite integral $(4x3 - 3 x2 + 4x + 2)dx A. 20 B. 18 C. 16 D. 24

Answer 1

The correct answer is A) 20.

To find the definite integral:

$$(4x^3 - 3x^2 + 4x + 2)dx$$

We must first expand the given function.

(4x^3 - 3x^2 + 4x + 2)dx = 4x^3 + 2dx

Then, we can evaluate the integral as follows:

$$\int4x^3dx = 4\int(x^3dx) = 4x^4+C$$