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Find the resultant of two forces one 6N due east other 8N due north​

1 Answer

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SolutioN:-

Using Resultant Formula:-


\sf \longrightarrow R =\sqrt{ {a}^(2) + {b}^(2) + 2ab \: \cos \: \theta }


\sf \longrightarrow R =\sqrt{ {6}^(2) + {8}^(2) + 2(6)(8) \: \cos \: 90\degree }


\sf \longrightarrow R = √( 6* 6 + 8* 8 + 2* 6 * 8 \: \cos \: 90\degree )


\sf \longrightarrow R =√( 36 + 64 + 96 \: \cos \: 90\degree )


\sf\longrightarrow R = √( 36 + 64 + 96 \: (0) )


\sf\longrightarrow R = √( 36 + 64 + 96 \: * 0 )


\sf\longrightarrow R = √( 36 + 64 + 0 )


\sf \longrightarrow R =√( 36 + 64 )


\sf\longrightarrow R = √( 100 )


\sf\longrightarrow R = √( 10* 10 )


\sf \longrightarrow R= 10 N

Therefore,

Answer :- 10 N ✅

User Alex Kutsko
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