Question

Find the resultant of two forces one 6N due east other 8N due north​

Answer 1

SolutioN:-

Using Resultant Formula:-

`\sf \longrightarrow R =\sqrt{ {a}^(2) + {b}^(2) + 2ab \: \cos \: \theta }`

`\sf \longrightarrow R =\sqrt{ {6}^(2) + {8}^(2) + 2(6)(8) \: \cos \: 90\degree }`

`\sf \longrightarrow R = √( 6* 6 + 8* 8 + 2* 6 * 8 \: \cos \: 90\degree )`

`\sf \longrightarrow R =√( 36 + 64 + 96 \: \cos \: 90\degree )`

`\sf\longrightarrow R = √( 36 + 64 + 96 \: (0) )`

`\sf\longrightarrow R = √( 36 + 64 + 96 \: * 0 )`

`\sf\longrightarrow R = √( 36 + 64 + 0 )`

`\sf \longrightarrow R =√( 36 + 64 )`

`\sf\longrightarrow R = √( 100 )`

`\sf\longrightarrow R = √( 10* 10 )`

`\sf \longrightarrow R= 10 N`

Therefore,

Answer :- 10 N ✅