Question

Tyler measures the angle of elevation to the top of a prominent skyscraper to be 57 If he is standing at a horizontal distance of 112 meters from the base of the skyscraper, what is the height of the skyscraper?

Expert Answer

Answer 1

Step-by-step explanation:

`\tan( \alpha ) = (o)/(a)`

Where the angle is 57°, the horizontal is 112 metres.

To find the vertical distance,

`o = a \tan( \alpha )`

`o = 112 \tan(57)`

`o = 172.46 \: metres`

Approximating to two decimal places.

therefore the height of the skyscraper is 172 .46 m.