Final answer:
To produce 0.80 mol of nitrogen, you would need 1.60 mol of ammonium perchlorate.
Step-by-step explanation:
To calculate the moles of ammonium perchlorate needed to produce 0.80 mol of nitrogen, we need to use the balanced chemical equation for the reaction. According to the given equation:
10Al(s) + 6NH4C1O4(s) → 4Al2O3 (s) + 2AlCl3 (s) + 12H₂O(g) + 3N2 (g)
We can see that for every 3 moles of nitrogen (N₂) produced, we need 6 moles of ammonium perchlorate (NH4C1O4). Therefore, we can set up a proportion:
(0.80 mol N₂) / (3 mol N₂) = (x mol NH4C1O4) / (6 mol NH4C1O4)
By cross-multiplying and solving for x, we find that x = 0.80 mol N₂ * (6 mol NH4C1O4 / 3 mol N₂) = 1.60 mol NH4C1O4.