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Radical 45g^3h^6 simple

User Ushi
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1 Answer

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Answer:
\[3\sqrt[3]{3} * \sqrt[3]{5} * g * h^2\]

Explanation:

To simplify this, we can break it down into prime factors and then take the cube root of each part:

1. Factorize the numerical part:
\(45 = 3^2 * 5\).

2. Break down the variable parts:
\(g^3\) and \(h^6\).

3. Take the cube root of each part:


\[\sqrt[3]{45g^3h^6} = \sqrt[3]{3^2 * 5 * g^3 * h^6} = \sqrt[3]{3^2} * \sqrt[3]{5} * \sqrt[3]{g^3} * \sqrt[3]{h^6} = 3\sqrt[3]{3} * \sqrt[3]{5} * g * h^2\]

So the simplified expression is:


\[3\sqrt[3]{3} * \sqrt[3]{5} * g * h^2\]

User Pyton
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