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A man flies a kite at a height of 120 m. The wind carries the kite horizontally away from him at a rate of 8 m/sec. How fast is the distance between the man and the kite changing when the kite is 130 m away from him?

120.3 m/sec
3.6 m/sec
3.1 m/sec
8 m/sec

User Jumpa
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2 Answers

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Final answer:

The rate at which the distance between the man and the kite is changing when the kite is 130 m away from him is 0 m/sec.

Step-by-step explanation:

To solve this problem, we can use the concept of related rates. Let's denote the distance between the man and the kite as x and the height of the kite as y. We are given that dy/dt (the rate at which the height is changing) is 0 m/sec since the kite is flying at a constant height. We are also given dx/dt (the rate at which the distance is changing) as 8 m/sec. We need to find dx/dt when x = 130 m:

Using the Pythagorean theorem, we can express the relationship between x and y as x^2 + y^2 = 120^2. Differentiating both sides of this equation with respect to time, we get 2x (dx/dt) + 2y (dy/dt) = 0. Since dy/dt is 0, the equation simplifies to 2x (dx/dt) = 0. Solving for dx/dt, we get dx/dt = 0 m/sec.

User Annada
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Final answer:

The rate at which the distance between the man and the kite is changing, when the kite is 130 m away, is calculated using the Pythagorean theorem and is found to be 3.1 m/sec.

Step-by-step explanation:

Calculating Rate of Change in Distance

Given that a kite flies horizontally away at a constant speed of 8 m/sec and its height above the ground remains constant at 120 m, we can represent the situation with a right triangle. The vertical height from the man to the kite is one leg (120 m), and the horizontal distance from the man to the point directly below the kite will be varying as time passes. At the moment when the kite is 130 m away from the man, we use the Pythagorean theorem to find the hypotenuse (the direct distance from the man to the kite). Let's denote the horizontal distance by x and the rate at which this distance changes by dx/dt = 8 m/sec, the direct distance by r, and the rate at which r changes by dr/dt.

We have:

Height (h) = 120 m (constant)

Horizontal distance (x) = ??? varies over time

Direct distance (r) = 130 m

Using the Pythagorean theorem:

r^2 = h^2 + x^2

130^2 = 120^2 + x^2

x^2 = 130^2 - 120^2

x = 50

Since x changes over time, we differentiate both sides of r^2 = h^2 + x^2:

2r x dr/dt = 2x x dx/dt

2 x 130 x dr/dt = 2 x 50 x 8

dr/dt = (50 x 8)/130

So, the rate at which the distance between the man and the kite is changing is 3.1 m/sec.

User MxWild
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