Question

Suppose that you are required to calculate the mass (m) of a certain number of Ar atoms (N'). (where N'= number of entities, N=Avogadro's number, m=mass and M= molar mass) a. [2 pts] Choose the correct operation for calculating the mass (m): (N=N)xM Done N'EN (N=N)XM N':M (N'xN)=M (NXM)-N NAM b. [3 pts ] Given that N' = 25.54x1080, the correct operation after substituting the correct values looks like: 25.54x10^80 - 6.022x10^23 Done (25.54x10^80 x 6.022x10^23) = 40 25.54x10^80 = 6.022x10^23 25.54x10^80 + 6.022x10^23 (25.54x10^80 = 6.022x10^23) x 40 (6.022x10^23 x 40) = 25.54x10^80 25.54*10^80 = 40

Answer 1

The correct operation for calculating the mass (m) of a certain number of Ar atoms (N') is: (N' x N) = M.

Explanation:

To determine the mass (m) of a certain number of Ar (Argon) atoms (N'), we employ the formula m = N' x M, where N' represents the number of entities, N signifies Avogadro's number, m denotes the mass, and M is the molar mass. Among the options provided, the accurate operation for calculating the mass is (N' x N) = M, where N' (the given number of Ar atoms) is multiplied by Avogadro's number (N) to yield the molar mass (M).

Substituting the given values into the equation helps solve the problem. If N' = 25.54x10^80, the correct operation involves multiplying N' by Avogadro's number (N = 6.022x10^23) to find M, the molar mass of the given number of Ar atoms. Therefore, the correct computation is (25.54x10^80) x (6.022x10^23) = M, which leads to determining the mass based on the provided quantities.

This mathematical process ensures that the correct relationship between the number of entities (N'), Avogadro's number (N), and the resulting molar mass (M) is maintained, providing the accurate calculation for determining the mass (m) of the specified number of Ar atoms.