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Factorisation-8th lesson6 6.2 how to solve
32x3+108y3

User Stevendesu
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Answer:

Hi,

Explanation:


Remember:\\\\a^3+b^3=(a+b)(a^2-ab+b^2)\\\\32x^3+108y^3\\\\=4(8x^3+27y^3)\\\\=4((2x)^3+(3y)^3)\\\\\boxed{=4(2x+3y)(4x^2-6xy+9y^2)}\\

User SubG
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