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The father is 48 years old and he has 21 years old son. How many years ago has father 10 times older than his son?

User Mzu
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Let's consider the number of years ago when the father was 10 times older than his son.

Let x be the number of years ago.

The father's age x years ago would be 48 - x, and the son's age x years ago would be 21 - x.

According to the given condition, the father's age x years ago was 10 times the son's age x years ago:

48 - x = 10 * (21 - x)

Now, we can solve this equation to find the value of x:

48 - x = 210 - 10x

Combining like terms:

9x = 210 - 48

9x = 162

Dividing both sides by 9:

x = 18

Therefore, 18 years ago, the father was 10 times older than his son.
User Itsatony
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