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Find the odd one out (a) fhko (b) cehl (c) zbej (d) xzcg

User MrDrews
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The odd man out in this set of options is C) zbej.

In this problem, we are presented with four choices of sets of letters, all of which have a pattern; however, we must identify the pattern that is different from the others.

(a) fhko

In this pattern, the first letter skips 1 letter to receive the second (f ⇒ h). To get the third letter, the second letter skips 2 (h k). Then, to get the fourth letter, the third letter skips 3 (k o).

(b) cehl

This pattern follows the same sequence as did option A. To get the second letter, the first letter skips 1 (c e). To get the third letter, the second letter skips 2 (e h). Then, to get the fourth letter, the third letter skips 3 (h l).

(c) zbej

This pattern seemingly follows the same as options A and B until the last letter (j). To get from z to b, 1 letter (A) is skipped (z b). To get from b to e, 2 letters are skipped (b e). To get from e to j, we must skip 4 letters (e j).

(d) xzcg

This pattern abides by the same foundations of options A and B. To get from x to z, one letter (Y) is skipped (x z). To get from z to c, two letters (A and B) are skipped (z c). Finally, to get from c to g, three letters (D, E, and F) are skipped (c g).

With all patterns aside from option C representing the same patterns, we find that option C is the odd one out.

User Martin Woodward
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