Question

A pure silver ring contains 2.80×10²² silver atoms. How many grams of silver atoms does it contain(molar mass of silver =108gmol⁻¹)

Answer 1

To find the mass of silver from the number of silver atoms, convert atoms to moles using Avogadro's number, then multiply the moles by the molar mass of silver to get the mass in grams. The mass of silver with 2.80 \u00d7 1022 silver atoms is 5.022 grams.

Step-by-step explanation:

To calculate the mass of silver (Ag) in grams from the number of atoms given, we first need to convert atoms to moles using Avogadro's number, which is 6.022 \u00d7 1023 atoms/mol. Here is the step-by-step process:

Multiply the moles of silver by the molar mass of silver, which is 108 g/mol, to find the mass in grams.

Let's do the calculation:

Number of silver atoms = 2.80 \u00d7 1022 atoms
Avogadro's number = 6.022 \u00d7 1023 atoms/mol

Moles of silver = (2.80 \u00d7 1022) / (6.022 \u00d7 1023)
Moles of silver = 0.0465 mol

Now, we multiply the moles by the molar mass of silver:
Mass of silver = 0.0465 mol \u00d7 108 g/mol
Mass of silver = 5.022 g