PLEASE HELP MEEEEEEE PLEASE PLEASE PLEASE PLEASE

asked Nov 7, 2024 138k views

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1 vote

Answer:

$(3p+4)(2p+5)\\=3p(2p+5)+4(2p+5)\\=6p^2+15p+8p+20\\=6p^2+23p+20$

$(n-1)(8n-2)\\=n(8n-2)-1(8n-2)\\=8n^2-2n-8n+2\\=8n^2-10n+2$

$(x+8)(x-7)\\=x(x-7)+8(x-7)\\=x^2-7x+8x-56\\=x^2+1x-56$

$(5x-1)(5x-6)\\=5x(5x-6)-1(5x-6)\\=25x^2-30x-5x+6\\=25x^2-35x+6$

Pezhvak answered Nov 14, 2024

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