Answer:
Explanation:
To find the value of k so that the given line has a slope of m = 1/3, we need to rearrange the equation into slope-intercept form (y = mx + b), where m represents the slope.
Starting with the given equation:
kx + 2y = 5
Let's isolate the y-term:
2y = -kx + 5
Divide both sides of the equation by 2:
y = (-k/2)x + 5/2
Now we can see that the coefficient of x is -k/2, which represents the slope. We want this slope to be equal to 1/3. Therefore, we have the equation:
-k/2 = 1/3
To solve for k, we can multiply both sides of the equation by -2/1:
(-2/1)(-k/2) = (-2/1)(1/3)
This simplifies to:
k = -2/3
So, the value of k that makes the given line have a slope of m = 1/3 is k = -2/3.