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Find the equation of the line that passes through the point (-9,10) and is perpendicular to the line y=3/2x-1/2

Write the equation using the​ slope-intercept form.

Find the equation of the line that passes through the point (-9,10) and is perpendicular-example-1
User Chuleta
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1 Answer

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Answer:

y = -2/3x +4

Explanation:

You want the slope-intercept form equation for the line through point (-9, 10) and perpendicular to y = 3/2x -1/2.

Slope

The perpendicular line will have a slope that is the opposite reciprocal of the slope of the given line. The slope of the given line is the coefficient of x, 3/2. Then the perpendicular line will have slope ...

m = -1/(3/2) = -2/3

Intercept

The y-intercept of the line can be found from ...

y = mx +b

b = y -mx = 10 -(-2/3)(-9) = 10 -6 = 4

Equation

The equation you want is ...

y = mx +b

y = -2/3x +4

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Additional comment

The equation can also be found by starting with the point-slope form and rearranging.

y -10 = -2/3(x +9)

y = -2/3x -6 +10 = -2/3x +4

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Find the equation of the line that passes through the point (-9,10) and is perpendicular-example-1
User Marco Scannadinari
by
7.8k points

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