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a car travels one third of a path with speed of50 and two third of a pathh with 20 its average speed will be

User Galloglass
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1 Answer

4 votes

Answer:

The average speed of the car will be approximately 4.1667 units.

Step-by-step explanation:

To calculate the average speed of the car, you can use the formula:

Average Speed = Total Distance / Total Time

In this case, the car travels one third of the path at a speed of 50 units and two thirds of the path at a speed of 20 units. Let's assume the total distance is D units (it doesn't affect the calculation), and we'll calculate the time taken for each segment of the path.

First segment (one third of the path at 50 units speed):

Distance = (1/3) * D

Speed = 50 units

Time = Distance / Speed = ((1/3) * D) / 50

Second segment (two thirds of the path at 20 units speed):

Distance = (2/3) * D

Speed = 20 units

Time = Distance / Speed = ((2/3) * D) / 20

Total time taken:

Total Time = Time for first segment + Time for second segment

Total Time = ((1/3) * D) / 50 + ((2/3) * D) / 20

Now, plug this value of Total Time back into the formula for average speed:

Average Speed = Total Distance / Total Time

Average Speed = D / (((1/3) * D) / 50 + ((2/3) * D) / 20)

Simplify the equation:

Average Speed = 1 / (((1/3) / 50) + ((2/3) / 20))

Average Speed = 1 / ((1/150) + (2/60))

Average Speed = 1 / (1/150 + 1/30)

Average Speed = 1 / (6/150 + 30/150)

Average Speed = 1 / (36/150)

Average Speed = 150 / 36

Average Speed ≈ 4.1667 units

The average speed of the car will be approximately 4.1667 units.

User Krash
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