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Samuel walks at a constant speed of 2,0 m-s-' from his home (A) to the shop (B) and then to his friend's house (C). a) Calculate the total distance that Samuel covers. b) Calculate how long this takes him in minutes. c) Calculate his displacement. d) Calculate his average velocity.

User Jhole
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1 Answer

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Let's solve each part step by step:

a) Total Distance Covered:

Samuel travels from home (A) to the shop (B) and then to his friend's house (C). The total distance covered is the sum of the distances between these points.

Distance from A to B = Distance from B to C = 2,0 m

Total distance = Distance AB + Distance BC = 2,0 m + 2,0 m = 4,0 meters

b) Time Taken:

Samuel's speed is given as 2,0 m/s. To calculate the time taken for the entire journey, we can use the formula:

Time = Distance / Speed

Total time = Total distance / Speed = 4,0 m / 2,0 m/s = 2,0 seconds

To convert seconds to minutes, divide by 60 (since there are 60 seconds in a minute):

Total time in minutes = 2,0 seconds / 60 = 0,0333 minutes (approximately)

c) Displacement:

Displacement is the shortest distance between the initial and final positions, considering both magnitude and direction. In this case, displacement is the straight-line distance from Samuel's home (A) to his friend's house (C), since he ends up at his friend's house.

Displacement = Distance AC = 2,0 meters

d) Average Velocity:

Average velocity is defined as the displacement divided by the time taken. In this case, we can use the displacement and the total time calculated above.

Average velocity = Displacement / Total time = 2,0 m / 2,0 s = 1,0 m/s

So, to summarize:

a) Total distance covered: 4,0 meters

b) Time taken: 0,0333 minutes (approximately)

c) Displacement: 2,0 meters

d) Average velocity: 1,0 m/s

User Saurabh Mishra
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