Answer:
₹1100
Explanation:
Let t = cost of 1 table.
Let c = cost of 1 chair.
"The cost of 4 tables and 3 chairs is ₹6950."
4t + 3c = 6950
"the table costs ₹250 more than the chair"
t = c + 250
We have a system of 2 simultaneous equations.
4t + 3c = 6950
t = c + 250
Since the second equation is already solved for t, we can use teh substitution method. Substitute c + 250 for t in the first equation.
4t + 3c = 6950
4(c + 250) + 3c = 6950
4c + 1000 + 3c = 6950
7c = 5950
c = 850
t = c + 250 = 850 + 250 = 1100
Answer: ₹1100