Final answer:
The kinetic energy of the bomb at the end of 10 seconds is 40590 J.
Step-by-step explanation:
To calculate the kinetic energy of an object, we can use the formula KE = 0.5 * mass * velocity^2.
Given that the mass of the bomb is 40 kg and it is dropped from a height of 1 km above the ground, we need to find its velocity at the end of 10 s.
Since the bomb is in free-fall, we can use the equation of motion s = ut + 0.5 * gt^2, where s is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time.
At the end of 10 s, the height of the bomb will be 1 km - (0.5 * 9.8 m/s^2 * 10 s)^2 = 1 km - 490 m = 510 m.
Using the equation v^2 = u^2 + 2gs, we can find the velocity at the end of 10 s as v = sqrt(2 * 9.8 m/s^2 * 510 m) = 45.05 m/s.
Now, we can calculate the kinetic energy using the formula KE = 0.5 * mass * velocity^2:
KE = 0.5 * 40 kg * (45.05 m/s)^2 = 40590 J.