234k views
0 votes
If the equations 4x-5y+14 and 5x-4y+13 are simultaneously true, then x-y=?

1 Answer

3 votes

Answer:

....we write a system

4x-5y+14=0

5x-4y+13=0

4x-5y=-14

5x-4y=-13

per combination:

-5(4x-5y=-14)

+4(5x-4y=-13)

-20x+25y=70

+20x-16y=-52

--->9y=18

--->y=18/9=2

we calculate x:

4x-5y=-14

4x-10=-14

4x=-14+10

x=-4/4=-1

solution(-1, 2)

we can calculate x-y:

-1-2=-3

--->x-y=-3

if the equations 4x - 5y + 14 = 0 and 5x - 4y + 13 = 0 are true simultaneously, then x - y is equal to -3.

Explanation:

User Rienix
by
8.2k points

No related questions found