Answer:
the degree of unsaturation for C5H6N2O2 is 9.5.
Step-by-step explanation:
To determine the degree of unsaturation (index of hydrogen deficiency) of a molecule, we need to calculate the number of pi bonds and rings present.
(a) C24H30:
To calculate the degree of unsaturation, we can use the formula: Degree of unsaturation = (2n + 2) - (H + X)/2
For C24H30:
Degree of unsaturation = (2 * 24 + 2) - (30 + 0)/2
= 50 - 15
= 35
Therefore, the degree of unsaturation for C24H30 is 35.
(b) C6H7BrCl2:
Degree of unsaturation = (2 * 6 + 2) - (7 + 2 + 2)/2
= 14 - 11/2
= 14 - 5.5
= 8.5
Therefore, the degree of unsaturation for C6H7BrCl2 is 8.5.
(c) C5H6N2O2:
Degree of unsaturation = (2 * 5 + 2) - (6 + 2 + 2)/2
= 12 - 5/2
= 12 - 2.5
= 9.5
Therefore, the degree of unsaturation for C5H6N2O2 is 9.5.