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The polynomial P(x) = x3 + 9x2 + 11x - 21. find p(0)

2 Answers

6 votes

Answer: p(0) = -21

Explanation:

Our task is to evaluate the expression:


\sf{p(x)=x^3+9x^2+11x-21} when x = 0.

So, we substitute 0 for x.


\sf{p(0)=0^3+9(0)^2+11(0)-21}

Evaluate.


\sf{p(0)=0+0+0-21}


\sf{p(0)=-21}

Therefore, p(0) = -21.

User Nirmit Dagly
by
8.5k points
4 votes

Answer:

P(0) = -21

Explanation:

P(x) = x³ + 9x² + 11x - 21 P(0)

P(0) = 0³ + 9(0)² + 11(0) - 21

P(0) = -21

User Xenoprimate
by
7.8k points

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