Question

16. A gas station sells three types of gas: Regular for $2.90 a gallon, Performance Plus for $3.15 a gallon, and Premium for $3.40 a gallon. On a particular day 4500 gallons of gas were sold for a total of $13,850. Two

times as many gallons of Regular as Premium gas were sold of 13,850. How many gallons of each type of gas were sold that day?
REGUALR = ______ gallons
PERFORMANCE PLUS = ________ gallons
PREMIUM = ______ gallons

Answer 1

The number of gallons of Regular and Performance Plus gas sold is 0, and the number of gallons of Premium gas sold is 4500.

Step-by-step explanation:

Let's assume the number of gallons of Premium gas sold is P. According to the question, two times as many gallons of Regular gas as Premium gas were sold. So, the number of gallons of Regular gas sold would be 2P. The total number of gallons sold is given as 4500, so we can write an equation: P + 2P + 4500 = 4500.

Now, let's solve the equation to find the value of P: P + 2P = 0, P + 2P -4P = 0(P equal to zero). So, the number of gallons of Regular gas sold would be 0, and the number of gallons of Performance Plus gas sold would be 0. Therefore, the number of gallons of Premium gas sold would be 4500.

Answer 2

A gas station sells three types of gas: Regular for $2.90 a gallon, Performance Plus for $3.15 a gallon, the gallons of each type of gas were sold that day are:

Regular = 1400 gallons.

Performance plus = 700 gallons

Premium = 750 gallons

Step-by-step explanation:

To solve this problem, we can set up a system of equations.

Let's say the number of gallons of Regular gas sold is represented by R, the number of gallons of Performance Plus gas sold is represented by P, and the number of gallons of Premium gas sold is represented by Pm.

From the given information, we know that:

R + P + Pm = 4500 (equation 1)

2.9R + 3.15P + 3.4Pm = 13850 (equation 2)

We're also given that there were twice as many gallons of Regular gas sold as Premium gas, so R = 2Pm.

Substituting R = 2Pm into equation 1, we get:

2Pm + P + Pm = 4500

3Pm + P = 4500

Substituting R = 2Pm into equation 2, we get:

2.9(2Pm) + 3.15P + 3.4Pm = 13850

5.8Pm + 3.15P + 3.4Pm = 13850

8.2Pm + 3.15P = 13850

Now we have a system of equations to solve: 3Pm + P = 4500 and 8.2Pm + 3.15P = 13850.

Solving this system of equations, we find that Pm = 700 gallons, P = 750 gallons, and R = 1400 gallons.

So therefore Pm = 700 gallons, P = 750 gallons, and R = 1400 gallons.