Answer:
center = (-4, 6)
scale factor = 2
Explanation:
J(-2, 2) J'(0, -2)
K(-4, 1) K'(-4, -4)
L(1, 0) L'(6, -6)
For dilation with center (a, b) & scale factor k:
- x' = k(x - a) + a
- y' = k(y - b) + b
xJ' = k(xJ - a) + a
0 = k(-2 - a) + a
-2k - ak + a = 0 ... [1]
xK' = k(xK - a) + a
-4 = k(-4 - a) + a
-4k - ak + a = -4 ... [2]
[1] & [2]
-2k - ak + a = 0
-4k - ak + a = -4
------------------------ (-)
2k = 4
k = 2
[1]
-2k - ak + a = 0
-2(2) - a(2) + a = 0
2a - a = -4
a = -4
yJ' = k(yJ - b) + b
-2 = 2(2 - b) + b
-2 = 4 - 2b + b
b = 6