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Write the quadratic equation in standard form:
-7x+8+2x^2=2-5x

User Palhares
by
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1 Answer

3 votes

Answer:

The quadratic equation in standard form is:


\sf \underline{ 2x^2 - 2x + 6= 0 }

Explanation:

The quadratic equation in standard form is:


\boxed{\sf ax^2 + bx + c = 0 }

where

  • a is the coefficient of the quadratic term
  • b is the coefficient of the linear term
  • c is the constant term

For:
\sf -7x+8+2x^2=2-5x

Let's solve the like terms by making right side 0.

Add 5x on both sides


\sf -7x+8+2x^2+5x=2-5x-5x


\sf -2x+8+2x^2=2

Subtract 2 on both sides


\sf -2x+8+2x^2-2=2 -2


\sf -2x+6+2x^2=0

In this equation,


\textsf{The quadratic term is }\sf 2x^2


\textsf{The linear term is -2x}


\textsf{The constant term is 6 }

So, the quadratic equation in standard form is:


\sf 2x^2 - 2x + 6= 0

User Maggie Pint
by
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