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The equation of the line in the xy-plane that has slope -(9)/(7) and passes through (-6,-1) is

User Bogdacutu
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Answer:

We can use the point-slope form of the equation of a line to find the equation of the line that has a slope of -(9/7) and passes through the point (-6, -1):

y - y1 = m(x - x1)

where m is the slope of the line, and (x1, y1) is the point that the line passes through.

Substituting m = -(9/7), x1 = -6, and y1 = -1, we get:

y - (-1) = -(9/7)(x - (-6))

Simplifying and solving for y, we get:

y + 1 = -(9/7)x - 54/7

y = -(9/7)x - 61/7

Therefore, the equation of the line that has a slope of -(9/7) and passes through the point (-6, -1) is y = -(9/7)x - 61/7.

User Null Set
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