Answer:
We can use the point-slope form of the equation of a line to find the equation of the line that has a slope of -(9/7) and passes through the point (-6, -1):
y - y1 = m(x - x1)
where m is the slope of the line, and (x1, y1) is the point that the line passes through.
Substituting m = -(9/7), x1 = -6, and y1 = -1, we get:
y - (-1) = -(9/7)(x - (-6))
Simplifying and solving for y, we get:
y + 1 = -(9/7)x - 54/7
y = -(9/7)x - 61/7
Therefore, the equation of the line that has a slope of -(9/7) and passes through the point (-6, -1) is y = -(9/7)x - 61/7.