Question

Calculate the K sp

​
of K 2
​
s if the equilibrium concentration of K +
is 0.56M and the equilibrium concentration of S 2−
is 0,182M.

Answer 1

The solubility product constant, Ksp, for K2S, given the equilibrium concentrations of K+ and S2-, is calculated to be 0.0570752 M3.

Step-by-step explanation:

To calculate the Ksp (solubility product constant) for K2S, we need to consider the dissolution reaction and its corresponding equilibrium constant expression. K2S dissociates in water to form two K+ ions and one S2- ion. The equilibrium expression for the solubility product constant, Ksp, is given by:

Ksp = [K+]2[S2-]

Substituting the provided equilibrium concentrations:

Ksp = (0.56 M)2(0.182 M)

After performing the calculations:

Ksp = (0.3136)(0.182) = 0.0570752 M3

So, the solubility product constant for K2S at the given concentrations is 0.0570752 M3.