Question

Solve using the quadratic formula. -4t^(2)-7t+5=0

Answer 1

Hello!

Answer:

`\Large \boxed{\sf t = (7 \pm √(129 ) )/(-8)}`

Explanation:

→ We want to solve this equation:

`\sf -4t^2 -7t+5=0`

→ It's a quadratic equation because it's on the form:

`\sf ax^2 + bx + c = 0`

→ Let's use the quadratic formula:

`\sf x = (-b \pm √(b^2 - 4ac) )/(2a)`

→ In our equation:

`\sf a = -4\\b = -7\\c = 5`

→ Let's apply the quadratic formula:

`\sf t = (-(-7) \pm √((-7)^2 - 4 * (-4) * 5 ) )/(2 * (-4))`

→ Simplify the equation:

`\boxed{\sf t = (7 \pm √(129 ) )/(-8)}`

Conclusion:

The solution of the equation
`\sf -4t^2 -7t+5=0` is
`{\sf (7 \pm √(129 ) )/(-8)`.