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Solve using the quadratic formula. -4t^(2)-7t+5=0

User Xbtsw
by
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1 Answer

3 votes

Hello!

Answer:


\Large \boxed{\sf t = (7 \pm √(129 ) )/(-8)}

Explanation:

→ We want to solve this equation:


\sf -4t^2 -7t+5=0

→ It's a quadratic equation because it's on the form:


\sf ax^2 + bx + c = 0

→ Let's use the quadratic formula:


\sf x = (-b \pm √(b^2 - 4ac) )/(2a)

→ In our equation:


\sf a = -4\\b = -7\\c = 5

→ Let's apply the quadratic formula:


\sf t = (-(-7) \pm √((-7)^2 - 4 * (-4) * 5 ) )/(2 * (-4))

Simplify the equation:


\boxed{\sf t = (7 \pm √(129 ) )/(-8)}

Conclusion:

The solution of the equation
\sf -4t^2 -7t+5=0 is
{\sf (7 \pm √(129 ) )/(-8).

User Jtlim
by
8.6k points

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