Final answer:
The 98% confidence interval for the proportion of Android phone users is (0.407, 0.792). The statement that must be true for the confidence interval at a new university is that it must be based on a representative sample to be valid.
Step-by-step explanation:
To construct a 98% confidence interval for the proportion of Android phone users among the student population, we use the formula:
Confidence interval = p ± Z*sqrt[(p(1-p))/n]
Where p is the sample proportion, Z is the Z-score for the confidence level, and n is the sample size.
Given that 21 out of 35 students in the sample use Android phones, we have:
- Sample proportion (p) = 21/35 = 0.6
- Sample size (n) = 35
The Z-score for a 98% confidence level is approximately 2.33 (from Z-tables).
Plugging these values into the formula:
Error Margin (E) = 2.33 * sqrt[(0.6*(1-0.6))/35]
Confidence interval = 0.6 ± E
After calculations, the correct confidence interval is option b. (0.407, 0.792).
As for the statements about what must be true about the confidence interval Nikki will calculate at a new university:
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- The confidence interval must be based on a representative sample to be valid
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- There is no guarantee that a correctly computed confidence interval should contain the true population parameter, although it's designed with that intention
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- While having a sample size of at least 30 can be a rule of thumb for the Central Limit Theorem to apply, it is not a rigid requirement
Therefore, the correct answer is a. It must be computed based on a representative sample to be valid.