Question

Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form Passing through (-8,-6) and parallel to the line whose equation is y=-3x+3

Answer 1

Answer: y = -3x - 30

Explanation:

Our task is to find the equation of the line, given that:

• it's parallel to y = -3x + 3; since parallel lines have equal slopes, the new line's slope is -3
• it passes through (-8,-6)

Since we know the slope and a point, we write the equation in point-slope:

`y-y_1=m(x-x_1)`

`y-(-6)=-3(x-(-8)`

`y+6=-3(x+8)`

`y+6=-3x-24`

`y=-3x-24-6`

`y=-3x-30`

Therefore, the equation is y = -3x - 30.

Answer 2

y + 6 = -3(x + 8)

y + 6 = -3x - 24

y = -3x - 30