Question

Solve the equation after making an app x^(4)-27x^(2)+50=0

Answer 1

`x=-5, \ -√(2), \ √(2), \ 5`

Explanation:

`\text{We can solve this by substituting in} \ u \ \text{for} \ x^(2) \ \text{to get the equation:} \\\\ u^(2) - 27u + 50 = 0 \\\\ \implies (u - 25)(u-2) = 0 \\\\ \implies u = 25, \ u = 2 \\ \\ \implies x^(2) = 25, \ x^(2) = 2 \\\\ \implies x = \pm5, \ x = \pm√(2)`