Answer:
(a) Let:
L be the lot size
D be the demand rate in units per day
S be the setup cost per lot
H be the holding cost per unit per day
The total demand in days necessary to exhaust the lot is L / D. The average inventory, in units, is given by L / 2. Therefore, the average inventory and setup cost per day can be calculated as:
Average inventory cost per day = (L / 2) * H
Setup cost per day = S / (L / D)
The objective is to minimize the sum of the average inventory cost per day and the setup cost per day. Therefore, the objective function is:
f(L) = (L / 2) * H + S / (L / D)
(b) To plot the objective function and compute the optimum lot size graphically, we need to choose specific values for D, S, and H. Let's say D = 5 units/day, S = $2000, and H = $40/unit/day.
Substituting these values into the objective function, we get:
f(L) = (L / 2) * 40 + 2000 / (L / 5)
To graphically determine the optimum lot size, we can plot f(L) as a function of L and find the minimum point on the graph. We can use a graphing calculator or software to do this.
Step-by-step explanation: