Solve using the square root property. x^(2)-98=0

Question

asked Aug 1, 2024 58.0k views

1 Answer

Asnaeb · Answer 1 · 2024-08-07T01:32:23+0000

Hello!

Answer:

$\Large \boxed{\sf x = \pm 7√(2)}$

Explanation:

→ We want to solve this equation:

$\sf x^2-98=0$

◼ Add 98 to both sides:

$\sf x^2-98+98=0+98$

◼ Simplify both sides:

$\sf x^2=98$

◼ Square root property:

We know that if
$\sf x^2 = a$ , then
$\sf x=\pm√(a)$ :

$\sf x= \pm√( 98)$

◼ Simplify the square root:

$\sf x= \pm√( 7^2 * 2)$

$\sf x= \pm(√( 7^2 )*√( 2) )$

$\sf x= \pm(7 * √( 2 ) )$

$\boxed{\sf x = \pm 7√(2)}$

So the solution of the equation
$\sf x^2-98=0$ is
$\sf \pm 7√(2)$ .