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Solve using the square root property. x^(2)-98=0

User Russell B
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1 Answer

2 votes

Hello!

Answer:


\Large \boxed{\sf x = \pm 7√(2)}

Explanation:

→ We want to solve this equation:


\sf x^2-98=0

Add 98 to both sides:


\sf x^2-98+98=0+98

Simplify both sides:


\sf x^2=98

◼ Square root property:

We know that if
\sf x^2 = a, then
\sf x=\pm√(a) :


\sf x= \pm√( 98)

Simplify the square root:


\sf x= \pm√( 7^2 * 2)


\sf x= \pm(√( 7^2 )*√( 2) )


\sf x= \pm(7 * √( 2 ) )


\boxed{\sf x = \pm 7√(2)}

So the solution of the equation
\sf x^2-98=0 is
\sf \pm 7√(2).

User Asnaeb
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