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A line that is perpendicular to y=-3x-10 passing through the point (6,8)

User Liorda
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1 Answer

12 votes

Answer: y = -1/3x + 10

Explanation:

To make it perpendicular change the reciprocals

So instead of 3x it'll be -1/3x and so it passes through the given points

plug the points

8 = -1/3(6) + b

8 = -2 + b

add 2 to both sides

10 = b

so the equation of a line thats perpendicular to y=-3x-10 and passes through

points (6,8) is

y = -1/3x + 10

User Stackato
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3.3k points