Answer:
The values of the exponents are:
a = 0
b = -1
c = 1
Therefore, the relation becomes: V = k * M^(-1) * T.
Step-by-step explanation:
To determine the values of the exponents a, b, and c in the relation V = kL^aM^bT^c, we can use dimensional analysis. In this approach, we analyze the dimensions of the variables involved (length, mass, and tension) and equate them to the dimensions of velocity (L/T).
Let's break down the dimensions of each variable:
V (velocity): [L]/[T]
L (length): [L]
M (mass): [M]
T (tension): [M][L]/[T]^2
Substituting these dimensions into the given relation:
[V] = [kL^aM^bT^c] = [k][L^a][M^b][T^c]
[L]/[T] = [k][L^a][M^b][M][L]/[T]^2
Now let's equate the dimensions on both sides of the equation:
[L]/[T] = [k][L^(a+1)][M^(b+1)][T^(c-2)]
Equating the dimensions of length on both sides:
1 = a + 1
Equating the dimensions of mass on both sides:
0 = b + 1
Equating the dimensions of time on both sides:
-1 = c - 2
c = 1
From the equation for mass, we found that b = -1, and from the equation for time, we found that c = 1. Using the equation for length, we have a = 0.
So, the values of the exponents are:
a = 0
b = -1
c = 1
Therefore, the relation becomes: V = k * M^(-1) * T.