Answer: the perimeter of the semicircle is approximately 30.85 units.
Explanation:
The perimeter of a semicircle is the sum of the length of its curved boundary (called the arc) and the diameter. In this case, we are given that the diameter of the semicircle is 12 units.
To determine the perimeter, we need to find the length of the arc. Since a semicircle is half of a full circle, the length of its arc is half of the circumference of a full circle with the same diameter.
The formula for the circumference of a circle is given by C = πd, where C represents circumference, π (pi) is a mathematical constant approximately equal to 3.14159, and d represents the diameter.
Therefore, the circumference of the full circle with a diameter of 12 units is:
C = πd
C = π(12)
C = 12π units
Since a semicircle is half of a full circle, the length of its arc is half of this circumference:
Arc length = (1/2)(12π)
Arc length = 6π units
Now, to calculate the perimeter of the semicircle, we add the length of its arc to the diameter:
Perimeter of semicircle = Arc length + Diameter
Perimeter of semicircle = 6π + 12 units
Therefore, the perimeter of the semicircle with a diameter of 12 units is 6π + 12 units or approximately 18.85 + 12 units (if we use the approximate value of π as 3.14159). therefore saying the awnser is 30.85 units. * i hope im right!*