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Find the indicated volume. Volume of the parallelpiped with three adjacent edges formed by ( 1, -6, 0), (1, -3, 8), and (-2, -7,-6) A. √94 B.94 C. 134 D. √134

User Alko
by
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1 Answer

6 votes

Explanation:

To find the volume of a parallelepiped formed by three adjacent edges, you can use the scalar triple product of the three vectors representing the edges. Given the vectors:

a = (1, -6, 0)

b = (1, -3, 8)

c = (-2, -7, -6)

The volume (V) of the parallelepiped formed by these vectors is given by:

V = |a · (b × c)|

Where × represents the cross product and · represents the dot product.

First, calculate the cross product of b and c:

b × c = [(b_y * c_z - b_z * c_y), (b_z * c_x - b_x * c_z), (b_x * c_y - b_y * c_x)]

= [(8 * (-6) - (-3) * (-6)), ((-3) * (-2) - 1 * (-6)), (1 * (-7) - 8 * (-2))]

= (-45, -12, 9)

Next, calculate the dot product of a and the cross product of b and c:

a · (b × c) = a_x * (b × c)_x + a_y * (b × c)_y + a_z * (b × c)_z

= 1 * (-45) + (-6) * (-12) + 0 * 9

= -45 + 72

= 27

Finally, take the absolute value of the dot product to get the volume:

V = |a · (b × c)| = |27| = 27

None of the provided answer choices (A. √94, B. 94, C. 134, D. √134) match the calculated volume of 27. It seems there might be a mistake in the options or in the given vectors.

User Uberto
by
8.1k points
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