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In a fluid, the velocity field is given by V=(3x+2y)I + (2z+3x²)j+(2t-3z)k. Determine;

1. The velocity components in the flow field
2. Speed at point (1,1,1)
3. The speed at t=2seconds at point (0,0,2. Classify the velocity field as steady/unsteady,uniform/non-uniform,123 dimensional

1 Answer

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The given velocity field is V = (3x + 2y)i + (2z + 3x²)j + (2t - 3z)k.

Velocity Components:

The velocity field is given in vector form as (Vx)i + (Vy)j + (Vz)k, where Vx, Vy, and Vz are the velocity components along the x, y, and z axes respectively.

So, from the given velocity field:

Vx = 3x + 2y

Vy = 2z + 3x²

Vz = 2t - 3z

Speed at Point (1, 1, 1):

To find the speed (magnitude of velocity) at a given point, we use the formula:

Speed = √(Vx² + Vy² + Vz²)

At point (1, 1, 1):

Vx = 3(1) + 2(1) = 5

Vy = 2(1) + 3(1²) = 5

Vz = 2(0) - 3(1) = -3

Speed = √(5² + 5² + (-3)²) = √59 ≈ 7.68

Speed at t = 2 seconds, Point (0, 0, 2):

Substituting t = 2 into the velocity field:

Vx = 3(0) + 2(0) = 0

Vy = 2(2) + 3(0²) = 4

Vz = 2(2) - 3(2) = -4

Speed = √(0² + 4² + (-4)²) = √32 ≈ 5.66

Classification of the Velocity Field:

Steady/Unsteady: The velocity field is unsteady because it contains the variable 't', indicating that the velocity changes with time.

Uniform/Non-uniform: The velocity field is non-uniform because the velocity components are functions of position (x, y, z) and time (t), which means the velocity changes both spatially and temporally.

1D/2D/3D: The velocity field is 3-dimensional since it has components along all three spatial dimensions (x, y, z).

The velocity components are Vx = 3x + 2y, Vy = 2z + 3x², and Vz = 2t - 3z. The speed at point (1, 1, 1) is approximately 7.68, and the speed at t = 2 seconds and point (0, 0, 2) is approximately 5.66. The velocity field is unsteady, non-uniform, and 3-dimensional.

User Harsimranb
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